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4y^2-64y+252=0
a = 4; b = -64; c = +252;
Δ = b2-4ac
Δ = -642-4·4·252
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-8}{2*4}=\frac{56}{8} =7 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+8}{2*4}=\frac{72}{8} =9 $
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